URGENT PLEASE HELP!!!!!

1. Which best describes the equation y/6=x?
A. The relationship shows an inverse variation with a constant of variation of -6
B. The relationship shows an inverse variation with a constant of variation of -1/6
C. The relationship shows an inverse variation with a constant of variation of 1/6
D. The relationship does not show an inverse variation.

2. If y varies inversely with x and y=5 when x=2.5, what is the value of y when x=20?
A. 0.1
B. 0.625
C. 0.3125
D. 1.6

3. The current, I, in a circuit varies inversely with the resistance, R. If the resistance is 12 when the current is 3, what is the resistance when the current is 6?
A. 1/6
B. 1.5
C. 6
D. 24

Respuesta :

(1)

we are given

[tex]\frac{y}{6} =x[/tex]

we can  find for y

multiply both sides by 6

[tex]\frac{y}{6}*6 =6*x[/tex]

[tex]y=6x[/tex]

we can see that y is directly proportional to x

so, option-D........Answer

(2)

y varies inversely with x

so, we can write it as

[tex]y=k\frac{1}{x}[/tex]

now, we are given

y=5 when x=2.5

so, we can plug it here

[tex]5=k\frac{1}{2.5}[/tex]

and then we can solve for k

[tex]5*2.5=2.5*k\frac{1}{2.5}[/tex]

[tex]k=12.5[/tex]

now, we can plug back

[tex]y=\frac{12.5}{x}[/tex]

we can plug x=20

[tex]y=\frac{12.5}{20}[/tex]

[tex]y=0.625[/tex].............Answer

(3)

we are given

The current, I, in a circuit varies inversely with the resistance, R

so, we can write it as

[tex]I=\frac{k}{R}[/tex]

we have R=12 when I=3

so, we can plug it

[tex]3=\frac{k}{12}[/tex]

now, we can solve for k

[tex]3*12=12*\frac{k}{12}[/tex]

[tex]k=36[/tex]

now, we can plug back

[tex]I=\frac{36}{R}[/tex]

we can plug R=6

[tex]I=\frac{36}{6}[/tex]

[tex]I=6[/tex]................Answer


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