Respuesta :
width = 13
length = 30
p=2l + 2w
86 = 2(2w+4) + 2w
86 = 4w + 8 + 2w
86= 6w + 8
78 = 6w
13 = w
86 = 2l + 2(13)
86 = 2l + 26
60 = 2l
30 = l
check your work.
l is 4 centimeters more than twice w
twice w = 26
plus 4 = 30
i hope you understand. ask questions if not
The perimeter of a rectangle is twice the sum of the length and the width
The width of the rectangle is 19.5 cm
The length of the rectangle is 23.5 cm
The reasons the length and width values of the rectangle are correct are given as follows;
The known parameters of the rectangle are;
Length of the rectangle, L = 4 cm + The width of the rectangle, W
The perimeter of the rectangle = 86 cm
Required:
To find the dimensions of the rectangle
Solution:
Let L, represent the length of the rectangle, and let W represent the width, we have;
L = 4 + W
The perimeter of the rectangle, P = 2·L + 2·W
Plugging in L = 4 + W into the equation for the perimeter gives;
P = 2·L + 2·W = 2×(4 + W) + 2·W = 8 + 4·W
P = 8 + 4·W
The perimeter, P = 86 cm (given)
Therefore;
P = 86 = 8 + 4·W
86 - 8 = 4·W
78 = 4·W
W = 78/4 = 19.5
The width of the rectangle, W = 19.5 cm
L = 4 + W = 4 + 19.5 = 23.5
The length of the rectangle, L = 23.5 cm
Learn more about finding the perimeter of a quadrilateral here:
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