AnikaMK
AnikaMK AnikaMK
  • 27-09-2018
  • Mathematics
contestada

How do I solve for X?

How do I solve for X class=

Respuesta :

tala32
tala32 tala32
  • 27-09-2018
We use the theory of Pythagoras because the triangle is right.

[tex]AB {}^{2} = AC {}^{2} + BC {}^{2} [/tex]
since AB = AC = x
[tex]8 {}^{2} = x {}^{2} + x {}^{2} [/tex]
[tex]64 = 2x {}^{2} [/tex]
[tex]32 = x {}^{2} [/tex]
[tex]x = \sqrt{32} [/tex]
[tex]x = \sqrt{16 } \times \sqrt{2} [/tex]
[tex]x = 4 \sqrt{2} [/tex]
Answer Link
suspho
suspho suspho
  • 27-09-2018

it is an isosceles right triangle, the hypotenuse is the diagonal of a square, the area of ​​the square is also diagonal by diagonal divided by two, so use the inverse formula

√(8*8:2) =

5.65


Answer Link

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