Answer:
The answer is 2.47 meters.
Explanation:
V = 3.8 m/s
Δt = 1.3s
vf = 0
it is asked to find S and a,
a = vf - vi ÷ t
a = 0 - 3.8 ÷ 1.3
a = 2.92 m/s²
S = vf + vi ÷ 2 x t
= (3.8 ÷ 2) x 1.3
= 2.47 meters.
Acceleration is the rate of change of velocity
The baseball's player's deceleration is approximately 2.923 m/s²
The reason the value for the acceleration is correct is as follows:
The known parameters of the baseball player;
The speed with which the player dashes towards the home plate, v₁ = 3.8 m/s
The time in wish the baseball player slides and stops, t = 1.3 s
The velocity of the player at the plate where she stops, v₂ = 0
Question: The missing part of the question as obtained online is appears to be as follows
Part A; What is the baseball player's acceleration
Solution:
Acceleration is given by the formula
[tex]Acceleration, \ a = \mathbf{\dfrac{v_2 - v_1}{\Delta t}}[/tex]
Therefore;
[tex]The \ acceleration \ of \ the \ player, \ \mathbf{a} = \dfrac{v_2 - v_1}{\Delta t} = \dfrac{0 - 3.8 \, m/s}{1.3 \, s} \approx \mathbf{ -2.923 \, m/s^2}[/tex]
The deceleration of the player, a ≈ 2.923 m/s²
Learn more about acceleration of a body here:
https://brainly.com/question/20369050
