Respuesta :

4x-3y=12


First pair (0,?)


4(0)-3y=12

-3y=12

Y = 12/-3

Y= -4


So first pair is (0, -4)


Second pair (?,0)


4x-3(0)=12

4x=12


X= 12/4


X= 3


Do same for rest .


Your table should be

X ,Y

(0,-4)

(3,0)

(-3,-8)

(3/4,-3)

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