We have to choose 3 people at random and give them separate posts.
Just to choose 3 from 17 : use combination
To choose 3 and give separate posts: use permutation
So we have to use permutation.
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It can be done is 17P3 ways.
[tex]{}^{17} P_3 = \frac{17!}{(17-3)!} \\ = \frac{17!}{14!} \\ =17 \times 16 \times 15 \\ = 4080[/tex]
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From the chosen 3, you have to select 2 at random for Senate.
Choose 2 from 3.
Number of ways = 3C2 = 3! / [ 2! × (3-2)! ] = 3! / 2! = 3
You can do it in 3 ways.