The granite loses 1.53 × 10⁸ J of heat.
The formula for the heat (q) transferred is
q = mCΔT
I shall assume that the specific heat capacity of granite is 0.790 J·°C⁻¹g⁻¹.
m = 3.580 × 10⁶ g; ΔT = T_f – T_i = -12.9 °C - 41.2 °C = -54.1 °C
∴ q = 3.580 × 10⁶ g × 0.790 J·°C⁻¹g⁻¹ × (-54.1 °C) = -1.53 × 10⁸ J
The granite block loses 1.53 × 10⁸ J.
