Question

I'd really appreciate the help on this question! I'll give the Brainliest!

Mike and Beth are saving money to go to Disney World. They need at least $1975 in order to go. Mike mows yards and Beth will wash cars to raise money. Mike charges $25 each time he mows a yard and Beth charges $15 for each car she washes. The number of cars that Beth wash is no more than four times the number of lawns Mike has scheduled to mow. Beth will wash at least 50 cars.

Write a set of constraints to model the problem, with x representing the number of lawns mowed and y representing the number of dogs walked.

Answer 1

you set up first that it has to be greater than or equal to 1975. then you make 25x + 15y is what they are doing to get the money. then you make an inequality for 4y is less than or equal to x. then y is greater than or equal to 50. i couldnt go any farther then that and im sorry i hope this helps you get some where

Answer 2

We will first define variables

Let Mike be M and Beth be B.

First inequality is 25M + 15B ≥ 1975 an the second is  B≤ 4M

When we replace B in the first inequality we get

25M + 15*4M ≥ 1975 => 25M + 60M ≥ 1975 => 85M ≥ 1975 =>

M ≥ 1975/85 => M ≥ 23.23 => M= 24

When we replace value for M in the second inequality we get

B ≤ 4*24 => B ≤ 96

We will check   25 * 24 + 15 * 96 = 600 + 1440 = 2040$ ≥ 1975$

That is correct!

If we accept M= 23 then B≤ 92

We will check again 25*23 + 15*92 = 575 + 1380 = 1955$ ≤ 1975$

That is incorrect!

Good luck!!!