The electric field strength of a point charge is inversely proportional to the square of the distance from the charge ... a lot like gravity.
If the magnitude of the field is (2E) at the distance 'd', then at the distance '2d', it'll be (2E)/(2²). That's (2E)/4 = 0.5E .
Answer:
8 E
Explanation:
The formula for the electric field at point P which is at a distance r from the charge Q due to the charge Q is given by
E = k Q / r^2
If a charge is at a distance d from the charge q, the electric field is given by
2E = k q / d^2 .... (1)
Let the electric field at a distance 1/2 d is E'
E' = k q / (d/2)^2
E' = 4 k q / d^2 = 4 x 2E (From equation (1)
E' = 8 E
