3 and 28
[tex]\frac{f}{g}[/tex] = [tex]\frac{(x^{2 +2x - 3)} }{(x^{2 - 9)} }[/tex]
[tex]\frac{f}{g}[/tex] (4) = [tex]\frac{(16 + 8 - 3)}{(16 - 9)}[/tex] = [tex]\frac{21}{7}[/tex] = 3
(f + g) = f(x) + g(x) = x² + 2x - 3 + x² - 9 = 2x² + 2x - 12
(f + g)(4) = 2(4)² + 2(4) - 12 = 32 + 8 - 12 = 28
