Question

A clerk was asked to change a $10 bill. She returned nine more dimes than nickels, and twenty one more quarters than dimes. How many coins of each did she return

Answer 1

Let x = number of nickels

x + 9 = dimes               (nine more dimes than nickels

x + 9 + 21 = quarters   (21 more qtrs than dimes

.05(x) + .1(x+9) + .25(x + 9 + 21)  = 10

.4x + 8.4 = 10

.4x = 1.6

x = 4     - nickels

x+ 9 = 13    - dimes

x + 30 = 34   - quarters

Hope this helps