Respuesta :
k = [tex]\frac{5}{2}[/tex]
using the ' laws of logarithms '
log x - log y = log ( [tex]\frac{x}{y}[/tex])
logx = logy ↔ x = y
logk - log(k - 2) = log5
log ( [tex]\frac{k}{(k - 2)}[/tex] =log 5
[tex]\frac{k}{(k - 2)}[/tex] = 5
5(k - 2) = k
5k - 10 = k
4k = 10 ⇒ k = [tex]\frac{10}{4}[/tex] = [tex]\frac{5}{2}[/tex]
