We have been given that Judy’s brother Sam has a collection of 96 comic books. We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as [tex]2\times 48=48\times 2=96[/tex]. Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as [tex]3\times 32=32\times 3=96[/tex]. Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.
Our question has been answered.
