What is the mass of 1.7 × 1023 atoms of zinc (Zn)?

A. 0.0143
B. 0.054
C. 19
D. 230

I really need help with this problem. I did the math and got 18.4, and I can't round it. Would it be C?

Respuesta :

Number of moles is defined as the ratio of given mass in g to the molar mass.

The mathematical formula is:

Number of moles = [tex]\frac{given mass in g}{molar mass}[/tex]   (1)

Number of zinc atoms is equal to [tex]1.7\times10^{23}[/tex], by Avogadro number, number of moles can be calculated.

As, 1 mol=[tex]6.022\times10^{23}[/tex] atoms, hence,

[tex]1.7\times10^{23}\times\frac{1 mol}{6.022\times10^{23} }[/tex]

= 0.2822 mol

Now, from formula (1), calculate mass in g (molar mass of zinc = 65.4 g/mol)

0.2822 mol = [tex]\frac{mass in g}{65.4 g/mol}[/tex]

mass in g  = [tex]{0.2822 mol \times 65.4 g/mol[/tex]

= 18.45588 g

Thus, by rounding off the above number, it will come near about 19 g approximately.

Hence, option (C) is the correct answer.



 



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