Question

solve for the perimeter and area of a rectangle that has a length of 4in. and a width of 2 in

Answer 1

The perimeter is either 10 (if the rectangle has two sides that are 4in and one side that is 2in) or 8 (if the rectangle has two sides that are 2in and one side that is 4in)

Answer 2

p=4+4+2+2
=8+4
=12in

A=l×w
=4×2
=8in^2