Respuesta :
The answer is 12.
If we represent the cars in this way:
Black cars A = 23
Red cars B = 9
Blue cars C = 17
White cars D = 25
Silver cars E = 21
Then sum of white and blue cars is D + C = 25 + 17 = 42
And the sum of silver and red cars is E + B = 21 + 9 = 30
Using the subtraction:
(D+C) - (E+B) = 42 - 30 = 12
Therefore, there are 12 more white and blue cars than silver and red cars.
If we represent the cars in this way:
Black cars A = 23
Red cars B = 9
Blue cars C = 17
White cars D = 25
Silver cars E = 21
Then sum of white and blue cars is D + C = 25 + 17 = 42
And the sum of silver and red cars is E + B = 21 + 9 = 30
Using the subtraction:
(D+C) - (E+B) = 42 - 30 = 12
Therefore, there are 12 more white and blue cars than silver and red cars.