Question

Given that f(x) = 6x2 + 72, find x.

Answer 1

We have been given that

$f(x) = 6x^{2} +72$

$f(x)-72=6x^{2}$

$\frac{f(x)-72}{6} =x^{2}$

$x=\sqrt{\frac{f(x)-72}{6} }$

Hence, $x=\sqrt{\frac{f(x)-72}{6} }$.

Answer 2

Answer:

Values of x are:

±2i√3

Step-by-step explanation:

We have to find x in f(x)=6x²+72

i.e. those values of x for which

6x²+72=0

Subtracting 72 from both sides, we get

6x² = -72

Dividing both sides by 6, we get

x² = -12

Taking square root on both sides, we get

x = ±2i√3

Hence, Values of x are:

±2i√3