MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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When x = 6, the expression on the left becomes
[tex] 4^2 + (6-3)^2 = 16 + 3^2 = 16+9=25 [/tex]
The expression on the right is
[tex] 8\cdot 4 - 4 = 32-4 = 28 [/tex]
So, the symbol you should put is
[tex] 25 < 28 [/tex]