A web page designer creates an animation in which a dot on a computer screen has a position of r⃗ =[ 4.2 cm +( 2.5 cm/s2 )t2]i^+( 5.5 cm/s )tj^ .find the average velocity of the dot between t=0 and t=2.0s. give your answer as a pair of components separated by a comma. for example, if you think the x component is 3 and the y component is 4, then you should enter 3,4. express your answer using two significant figures.

Respuesta :

we are given

[tex]r(t)=(4.2cm+(2.5cm/s^2)t^2)i+(5.5cm/s)tj[/tex]

Firstly, we will plug t=0 and t=2

Calculation of r(0):

[tex]r(0)=(4.2cm+(2.5cm/s^2)*0^2)i+(5.5cm/s)*0j[/tex]

[tex]r(0)=4.2i+0j[/tex]

Calculation of r(2):

[tex]r(2)=(4.2cm+(2.5cm/s^2)*2^2)i+(5.5cm/s)*2j[/tex]

[tex]r(2)=(4.2+5)i+(11)j[/tex]

[tex]r(2)=(9.2)i+(11)j[/tex]

Average velocity:

now, we can use formula

[tex]v=\frac{r(2)-r(0)}{2-0}[/tex]

now, we can plug values

[tex]v=\frac{((9.2)i+(11)j)-(4.2i+0j)}{2-0}[/tex]

[tex]v=\frac{5i+11j}{2-0}[/tex]

[tex]v=(2.5cm/s) i+(5.5cm/s)j[/tex]..............Answer


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