Answer:- 0.00353 moles
Solution:- We are asked to calculate the moles of NaOH needed to neutralize 15.0 mL of 0.235 M HCl solution. We write the balanced equation that tell us the mol ratio they react in.
[tex]NaOH+HCl\rightarrow H_2O+NaCl[/tex]
From the balanced equation, they react in 1:1 mol ratio. It means moles of NaOH needed to neutralize HCl would be equivalent to the moles of HCl.
Moles of HCl are calculated from given molarity and volume and multiplied by mol ratio to get the moles of NaOH as:
[tex]15.0mL(\frac{1L}{1000mL})(\frac{0.235molHCl}{1L})(\frac{1molNaOH}{1molHCl})[/tex]
= 0.00353 mol NaOH
Hence, 0.00353 moles of NaOH are needed to neutralize given solution of HCl.
