Calculate the energy to heat two cubes (gold and aluminum) each with a volume of 10.0 cm3 from 15 °c to 25 °c.

Respuesta :

Energy required to heat a mass [tex]m[/tex] having specific heat capacity [tex]c[/tex] causing a temperature difference of [tex]\Delta T[/tex] is given by:

[tex]E=mc\Delta T[/tex]

a)gold

Density [tex]d=19.32 g/cm^3[/tex]

Volume, [tex]V=10cm^3[/tex](given)

Mass of gold, M=d×V

[tex]M=19.32g/cm^3\times10cm^3=193.2g[/tex]

Specific heat capacity of gold, [tex]c=0.129J/g ^oC[/tex]

[tex]\Delta T=25^oC-15^oC=10^oC[/tex]

[tex]\Rightarrow E=mc\Delta T=193.2g\times 0.129J/g ^oC \times 10^oC=249.2J[/tex]

b)Aluminium

Density [tex]d=2.7g/cm^3[/tex]

Volume, [tex]V=10cm^3[/tex](given)

Mass of gold, M=d×V

[tex]M=2.7g/cm^3\times10cm^3=27g[/tex]

Specific heat capacity of gold, [tex]c=0.902J/g ^oC[/tex]

[tex]\Delta T=25^oC-15^oC=10^oC[/tex]

[tex]\Rightarrow E=mc\Delta T=27g\times 0.902J/g ^oC \times 10^oC=243.5J[/tex]



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