Help with the two questions above
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8. y - 8 = - [tex]\frac{1}{2}[/tex] ( x + 16)
The equation of a line in ' point-slope form ' is
y - b = m( x - a)→ ( where m is slope and ( a ,b) a point on the line )
slope = (-2 - 8 )/(4 + 16) = (-10)/20 = - [tex]\frac{1}{2}[/tex]
using m = - [tex]\frac{1}{2}[/tex] and (a , b) = (-16 , 8)
y - 8 = - [tex]\frac{1}{2}[/tex] ( x + 16)
9. y- intercept = ( 0 , - 3) and x- intercept = ( 4 , 0)
to find intercepts
let y = 0 and solve for x
let x = 0 and solve for y
x = 0 → 4y + 12 = 0 ⇒ 4y = - 12 ⇒ y = - 3 ⇒ ( 0 , - 3 )
y = 0 → 3x = 12 ⇒ x = 4 ⇒ ( 4 , 0 )