Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Write the equation of the given circle. center (3, 3) radius of 2

Answer 1

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{3}{ h},\stackrel{3}{ k})\qquad \qquad radius=\stackrel{2}{ r} \\\\[-0.35em] ~\dotfill\\\\ (x-3)^2+(y-3)^2=2^2\implies (x-3)^2+(y-3)^2=4$

Answer 2

Answer:

Step-by-step explanation:

We want to write the equation of a circle with given center point and radius. Then, we just need the recall from basic analytic geometry the equation of the circle with known center and radius.

The general equation of a circle is

$(x-h)^2+(y-k)^2=r^2$

where $r$ stands for the radius of the circle, $h$  and $k$ stand for the X-coordinate and Y-coordinate respectively of the center of the circle.

In this particular case, $r=2$, $h=3$ and $k=3$. Thus, the equation of the circle is

$(x-3)^2+(y-3)^2=4$.