Question

100 points nani?!?!

Find the value of the following expression:

(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28


Write your answer in simplified form. Show ALL of your steps.


Don't post random useless answers ( ‾ ʖ̫ ‾)
thx

Answer 1

(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28

First set of parenthesis:

2^8 = 256, 3^-5 = 0.00411522, 6^0 = 1

(256 * 0.00411522 * 1) = 1.05349794

1.05349794^-2 = 0.90101623

Second set of parenthesis:

3^-2 = 0.1111, 2^3 = 8

(0.111 / 8) = 0.0138

0.0138^4 =  0.00000003721088

Third set: 2^28 = 268435456

Final: 0.90101623 * 0.00000003721088 * 268435456 =  9

(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28 = 9