Question

what is the point slope form of an equation for the line that has the indicated slope and contains the given point slope= 1.3;(-6.1,5.3)

Answer 1

y - 5.3 = 1.3 (I x + 6.1 )

the equation of a line in ' point- slope form ' is

y - b = m (x - a) → m is the slope and ( a , b ) a point on the line

here m = 1.3 and ( a , b ) = ( - 6.1 , 5.3 )

y - 5.3 = 1.3 ( x -( - 6.1)) ⇒ y - 5.3 = 1.3 ( x + 6.1 )

Answer 2

The point-slope form of the equation of the line is: $y - 5.3 = 1.3(x + 6.1)$

Given:

slope of the line = 1.3

point of the line = $(-6.1,5.3)$

The equation of a line represented in point-slope form can be expressed as:

$y - b = m(x - a)$

Where,

$slope (m) = 1.3\\point (a, b) = (-6.1, 5.3)$

Substitute the values into the point-slope equation

$y - 5.3 = 1.3(x - (-6.1))\\y - 5.3 = 1.3(x + 6.1)$

The point-slope form of the equation of the line that contains a slope value of 1.3 and a point (-6.1, 5.3) is $y - 5.3 = 1.3(x + 6.1)$

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