This is a complicated question because part of the paddle is submerged, so the effective radius is somewhat less than r=0.68 feet. We'll ignore that.
We have f=14 revolutions per minute so the tip of our paddles moves at
[tex]v = 2\pi r f[/tex]
That's it except we'll get the result in feet per minute which we have to convert to mph.
[tex] v= 2\pi(0.68\textrm{ feet} )(14 \textrm{ per minute}) \times \dfrac{1 \textrm{ mile}}{5280 \textrm{ feet}} \times \dfrac{60 \textrm{ minutes}}{\textrm{hour}}[/tex]
[tex]v = 0.679726 \textrm{ miles per hour}[/tex]
Answer: A
That's oddly close to the radius in feet because [tex]2\pi(14)(60)\approx 5278[/tex].