Question

The equation y-5=6(x+1) is written in point-slope form. What is the equation written in slope-intercept form?
a. y = 6x + 11
b. y = 6x – 1
c. y = 6x – 4
d. y = 6x + 6
(please hurry i will mark brainliest lol)

Answer 1

Your answer is A.

y - 5 = 6(x + 1)

y - 5 = 6x + 6

7 = 6x + 11

Answer 2

a. y = 6x + 11

distribute and rearrange into slope-intercept form.

y - 5 = 6x + 6

add 5 to both sides

y = 6x + 6 + 5 ⇒ y = 6x + 11