Question

given: K is between H and J, HK=2x-5, KJ=3x+4, and HJ=24. what is the value of x?

Answer 1

$\bf \boxed{H}\underset{\leftarrow 24\to\qquad \qquad }{\stackrel{2x-5}{\rule[0.35em]{10em}{0.25pt}}K\stackrel{3x+4}{\rule[0.35em]{15.5em}{0.25pt}}\boxed{J}} \\\\\\ \stackrel{HJ}{24}=\stackrel{HK}{(2x-5)}+\stackrel{KJ}{(3x+4)}\implies 24=5x-1\implies 25=5x \\\\\\ \cfrac{25}{5}=x\implies 5=x$