An archer needs to hit a bullseye on a target at eye level of 60ft away. If the archer fires the arrow from the eye level with a speed of 47ft/s at an angle of 25.0 degrees above the horizontal, will the arrow hit the target
The time of fly of a projectile to the same level as it was launched is 2(v_y)/g=2(47sin(25))/g. We multiply this by the v_x to get the distance. Thus, the distance is 2(47sin(25))/g*47cos(25)=86.2. This is a overshoot!
