Respuesta :

Let's assume

point K as (x,y)

M is the midpoint of JK

so, other point as J(0, 11)

M(-3,2)

[tex](-3,2)=(\frac{0+x}{2},\frac{11+y}{2})[/tex]

now, we can compare both sides

Calculation of x-coordinate:

we get

[tex]-3=\frac{0+x}{2}[/tex]

[tex]x=-6[/tex]

Calculation of y-coordinate:

we get

[tex]2=\frac{11+y}{2}[/tex]

[tex]11+y=4[/tex]

[tex]y=-7[/tex]

so, we will get point K

K=(-6,-7)............Answer

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