Respuesta :

x²+10x+41=0

using x=(-b±√b²-4ac)½

where a= 1

b=10

c=41


x= (-10±√10²-4×1×41)½

x=-5 ± √(100-164)

x=-5±√(-64)½

x=-5±4i

x=-5+4i or -5-4i  

where i= √-1

ANSWER: x=-5+4i or -5-4i  

ACCESS MORE