Respuesta :
The given compound is:
Ti6Al4V
1 mole of Ti6Al4V contains 6 moles of Ti
therefore, 5 moles of Ti6Al4V will have: 5 * 6/1 = 30 moles of Ti
Now,
1 mole of Ti contains 6.023 * 10^23 atoms of Ti
therefore, 30 moles of Ti will be composed of: 30 *6.023 * 10^23/1
= 1.807 * 10^25 atoms
Thus, 5 moles of Ti6Al4V will have 30 moles of Ti which in turn corresponds to 1.807*10^25 atoms of Ti.
Answer : The number of moles of Ti present in 5.00 moles of [tex]Ti_6Al_4V[/tex] are 30.
Explanation : Given,
Moles of [tex]Ti_6Al_4V[/tex] = 5.00 moles
Now we have to determine the moles of Ti.
In [tex]Ti_6Al_4V[/tex], there are 6 moles of Ti, 4 moles of Al and 1 mole of V.
As, 1 mole of [tex]Ti_6Al_4V[/tex] contains 6 moles of Ti
So, 5.00 mole of [tex]Ti_6Al_4V[/tex] contains [tex]5.00\times 6=30[/tex] moles of Ti
Hence, the number of moles of Ti present in 5.00 moles of [tex]Ti_6Al_4V[/tex] are 30.