Respuesta :

The given compound is:

Ti6Al4V

1 mole of Ti6Al4V contains 6 moles of Ti

therefore, 5 moles of Ti6Al4V will have: 5 * 6/1 = 30 moles of Ti

Now,

1 mole of Ti contains 6.023 * 10^23 atoms of Ti

therefore, 30 moles of Ti will be composed of: 30 *6.023 * 10^23/1

    = 1.807 * 10^25 atoms

Thus, 5 moles of Ti6Al4V will have 30 moles of Ti which in turn corresponds to 1.807*10^25 atoms of Ti.

Answer : The number of moles of Ti present in 5.00 moles of [tex]Ti_6Al_4V[/tex] are 30.

Explanation : Given,

Moles of [tex]Ti_6Al_4V[/tex] = 5.00 moles

Now we have to determine the moles of Ti.

In [tex]Ti_6Al_4V[/tex], there are 6 moles of Ti, 4 moles of Al and 1 mole of V.

As, 1 mole of [tex]Ti_6Al_4V[/tex] contains 6 moles of Ti

So, 5.00 mole of [tex]Ti_6Al_4V[/tex] contains [tex]5.00\times 6=30[/tex] moles of Ti

Hence, the number of moles of Ti present in 5.00 moles of [tex]Ti_6Al_4V[/tex] are 30.

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