Enter the symbol of a sodium ion, Na+, followed by the formula of a sulfate ion, SO42−. Separate the ions with a comma only—spaces are not allowed. Express your answers as ions separated by a comma.

Respuesta :

Na⁺,SO₄²⁻ is the answer

Further explanation

An ion is an atom or molecule that has a net electrical charge. There are many ions, one of them are sodium ion and sulfate ion.

SO₄²⁻ or Sulfate is a naturally occurring polyatomic ion that consist of a central sulfur atom surrounded by four oxygen atoms with occured widely in everyday life. Sodium ions are important for regulation of blood and body fluids, transmission of nerve impulses, heart activity, and certain metabolic functions.

Whereas Na⁺ or Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sulfate ion is a very weak base. Therefore sulfate ion undergoes negligible hydrolysis in aqueous solution.

Enter the symbol of a sodium ion, Na⁺, followed by the formula of a sulfate ion, SO₄²⁻. Separate the ions with a comma only—spaces are not allowed. Express your answers as ions separated by a comma. Therefore the answer is: Na⁺,SO₄²⁻

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Answer details

Grade:  9

Subject:  Chemistry

Chapter:  Introduction to Mastering Chemistry

Keywords: sodium ion, sulfate ion, ions, Chemistry, symbol

The respective symbols of sodium and sulphate ions are [tex]\boxed{{\text{N}}{{\text{a}}^ + },{\text{ SO}}_4^{2 - }}[/tex].

Further explanation:

The species that are produced after loss or gain of electrons are known as ions. Since ions are charged entities, these can be either positively charged or negatively charged. The positively charged ions are formed by the loss of electrons from the neutral atom and are known as cations. The negatively charged ions are called anions and are formed by the gain of electrons to the neutral atom.

The formation of anion occurs as follows:

 [tex]{\text{A}}\left( {{\text{Neutral atom}}} \right) + {e^ - } \to {{\text{A}}^ - }\left( {{\text{Anion}}} \right)[/tex]

The formation of cation occurs as follows:

 [tex]{\text{C}}\left( {{\text{Neutral atom}}} \right) - {e^ - } \to {{\text{C}}^ + }\left( {{\text{Cation}}} \right)[/tex]

The atomic number of Na is 11 so it has a configuration of [tex]1{s^2}2{s^2}2{p^6}3{s^1}[/tex]. It easily loses its 3s electron to form [tex]{\text{N}}{{\text{a}}^ + }[/tex] whose configuration becomes [tex]1{s^2}2{s^2}2{p^6}[/tex]. These ions are beneficial for heart activity, regulation of blood and body fluids and in transmission of nerve impulses. The formation of [tex]{\text{N}}{{\text{a}}^ + }[/tex] occurs as follows:

 [tex]{\text{Na}}\left( {1{s^2}2{s^2}2{p^6}3{s^1}} \right) - {e^ - } \to {\text{N}}{{\text{a}}^ + }\left( {1{s^2}2{s^2}2{p^6}} \right)[/tex]

[tex]{\text{SO}}_4^{2 - }[/tex] is a polyatomic ion that involves a central sulphur atom surrounded by four oxygen atoms and has a charge of -2 on it. These ions are used as cleansing agents in soaps and shampoos.

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Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic compounds

Keywords: ions, cations, anions, loss, gain, electrons, Na, Na+, A, C, A-, C+, atomic number, configuration, formation.

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