Respuesta :
This is a difference of squares. Every time you have the difference between two squares, you can factor it as the product between the sum and the difference of the roots:
[tex] a^2-b^2 = (a+b)(a-b) [/tex]
In your case, the squares are
[tex] y^2 \to \text{the square of } y [/tex]
[tex] 16 \to \text{the square of } 4 [/tex]
So, the difference between the squares, [tex] y^2-16 [/tex] can be written as the multiplication between the sum and difference of the roots:
[tex] y^2-16=(y+4)(y-4) [/tex]
I think it is the sum of cubes because if you add them, they become cubes.