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Identify the factoring pattern: y 2 −16=(y+4)(y−4) y2-16=(y+4)(y-4)
Difference of Squares
Perfect Square Trinomial
Difference of Cubes
Sum of Cubes

Respuesta :

This is a difference of squares. Every time you have the difference between two squares, you can factor it as the product between the sum and the difference of the roots:

[tex] a^2-b^2 = (a+b)(a-b) [/tex]

In your case, the squares are

[tex] y^2 \to \text{the square of } y [/tex]

[tex] 16 \to \text{the square of } 4 [/tex]

So, the difference between the squares, [tex] y^2-16 [/tex] can be written as the multiplication between the sum and difference of the roots:

[tex] y^2-16=(y+4)(y-4) [/tex]

I think it is the sum of cubes because if you add them, they become cubes.

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