Question

please help!!!!


what is the average rate of change of the function g(x) = 3(2x) - 6 over the interval [0,3]? Show all work.

Answer 1

The average rate of change (m) of function g(x) on interval [a, b] is given by

... m = (g(b) -g(a))/(b -a)

Here, we have

• g(3) = 723
• g(0) = -5

so the average rate of change is

... m = (723 -(-5))/(3 - 0) = 728/3 = 242 2/3

Answer 2

Answer:

The average rate of the function g(x)=6

Step-by-step explanation:

We are given that a function $g(x)=3(2x)-6$ on the interval [0,3]

We have to find the value of rate of change of the given  function over the interval [0,3]

To find the value of average rate of change of the function we apply slope formula

Average rate=Slope=m=$\frac{y_2-y_1}{x_2-x_1}$

Let a=0, b=3

Now, $g(a)=3(2\cdot0)-6=-6$

g(b)=$3(2\cdot3)-6=18-6=12$

Now, the average rate of the function g(x)=$\frac{g(b)-g(a)}{b-a}$

Average rate of the function g(x)=$\frac{12-(-6)}{3-0}$

Average rate of the function g(x)=$\frac{18}{3}=6$

Hence, the average rate of the function g(x)=6

Answer :6