abigail76531
abigail76531 abigail76531
  • 18-09-2018
  • Mathematics
contestada

I was wondering how to do this.

I was wondering how to do this class=

Respuesta :

jdoe0001 jdoe0001
  • 18-09-2018

[tex]\bf \cfrac{3}{k}=-\cfrac{8}{k+8}\implies \cfrac{3}{k}=\cfrac{-8}{k+8}\implies \stackrel{cross-multiplying}{3(k+8)=-8(k)}\implies 3k+24=-8k \\\\\\ 11k=-24\implies k=-\cfrac{24}{11}[/tex]

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