Question

What substitution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0 as a quadratic equation?

Answer 1

$16(x^3+1)^2-22(x^3+1)-3=0\\\\\text{substitute}\ t=x^3+1\\\\16t^2-22t-3=0$

Answer 2

Answer:B on edge

Step-by-step explanation: