Question

solve on the interval [0,2pi) 3cscx-1=2

a)pi/6,5pi/6
b)pi/3,5pi/3
c)2pi/3,4pi/3
d)pi/2

Answer 1

Answer:

It is pi/2

Step-by-step explanation:

Answer 2

The value of x for 3cosec x-1=2 on the interval [0, 2$\pi$) is $\pi$

How to solve the equation ?

Given that, 3cosec x-1 = 2  .............(1)

We have to substitute u for cosec x,

Then, the equation (1) becomes,

3u-1 = 2

⇒ 3u = 2+1

⇒ 3u = 3

⇒ u = 3/3

⇒ u = 1

Now, putting cosec x in place of u, we get,

cosec x = 1

⇒ cosec x = cosec 90°

⇒ x = $\pi$  ,where $\pi$ is in the interval [0, 2$\pi$)

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