Question

PLEASE HELP FAST!!!!!!!! Which two values of x are roots of the polynomial below?

x2 - 3x + 5

Answer 1

Given a quadratic equation

$ax^2+bx+c=0$

you can find its solutions with the following formula:

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

You equation is identified by the coefficients

$x^2 - 3x + 5 \iff a = 1,\ b = -3,\ c = 5$

Which means the solutions are

$\dfrac{3 \pm \sqrt{9-4\cdot 5}}{2} = \dfrac{3 \pm \sqrt{-11}}{2}$

So, the answers are B and D

Answer 2

Following are the calculation to the roots:

Given:

$x^2-3x+5$

To find:

roots=?

Solution:

$\to x^2-3x+5$

Compare the value with the standard quadratic equation:

$\to x^2-3x+5\\\\\to ax^2+bx+c\\\\-------- \\\\\to a= 1\\\\\to b= -3\\\\\to c= 5$  

Using the Shri dharacharya formula:

$\to x= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Putting the value into the above formula:  

$= \frac{-(-3) \pm \sqrt{(-3)^2 - 4\times 1 \times 5 }}{2 \times 1} \\\\= \frac{3 \pm \sqrt{ 9 - 20 }}{2} \\\\= \frac{3 \pm \sqrt{ -11 }}{2} \\\\= (\frac{3 + \sqrt{ -11 }}{2} , \frac{3 - \sqrt{ -11 }}{2})$

Therefore, the answer is "Option B and Option D "

Learn more about the roots:

brainly.com/question/12912962