Calculate the force of gravity on the 0.50-kg mass if it were 6.4×106 m above earth's surface (that is, if it were two earth radii from earth's center).

Respuesta :

Radius of Earth is given as

[tex]R = 6.4 * 10^6 m[/tex]

now here the height from the surface of earth is same as that of radius

[tex]h = 6.4 * 10^6 m[/tex]

now here the acceleration due to gravity at this height is given as

[tex]g' = \frac{GM}{(R+h)^2}[/tex]

[tex]g' = \frac{GM}{4R^2}[/tex]

[tex]g' = \frac{g}{4}[/tex]

now the force of gravity on the given object will be

[tex]F = mg'[/tex]

[tex]F = m*\frac{g}{4}[/tex]

[tex]F = 0.5 * \frac{9.8}{4}[/tex]

[tex]F = 1.225 N[/tex]

so the force of gravity on it is 1.225 N

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