Radius of Earth is given as
[tex]R = 6.4 * 10^6 m[/tex]
now here the height from the surface of earth is same as that of radius
[tex]h = 6.4 * 10^6 m[/tex]
now here the acceleration due to gravity at this height is given as
[tex]g' = \frac{GM}{(R+h)^2}[/tex]
[tex]g' = \frac{GM}{4R^2}[/tex]
[tex]g' = \frac{g}{4}[/tex]
now the force of gravity on the given object will be
[tex]F = mg'[/tex]
[tex]F = m*\frac{g}{4}[/tex]
[tex]F = 0.5 * \frac{9.8}{4}[/tex]
[tex]F = 1.225 N[/tex]
so the force of gravity on it is 1.225 N