Question

A new star has been discovered that has a peak electromagnetic wavelength of 400.00 nm. What is the star's surface temperature?

Answer 1

As per Wein's displacement law

the peak intensity wavelength is related to its temperature

it is given by relation

$\lambda = \frac{b}{T}$

here given that

$\lambda = 400 nm$

$b = 2.89 * 10^{-3}$

now from above formula

$400 * 10^{-9} = \frac{2.89 * 10^{-3}}{T}$

$T = \frac{2.89 * 10^{-3}}{400 * 10^{-9}}$

$T = 7225 K$

so temperature of the star will be 7225 Kelvin

Answer 2

The surface temperature of the new star which is discovered with peak electromagnetic wavelength of 400.00 nm is 7225 kelvin.

What is surface temperature?

Surface temperature of an object is the temperature at the surface or the outside plane of that object.

The surface temperature of a object is given by the Wien's law as,

$T=\dfrac{b}{\lambda}$

Here, λ is the wavelength and (b) is the Wien's displacement constant.

The electromagnetic wavelength of the star is given as 400.00 nm. Put the value of this wavelength in the Wien's law to find the star's surface temperature as,

$T=\dfrac{b}{400\times10^{-9}}$

The value of Wien's displacement constant is $2.89\times10^{-3}\rm mK$. Thus put the value in the above equation as,

$T=\dfrac{2.89\times10^{-3}}{400\times10^{-9}}\\T=7225\rm K$

Thus, the surface temperature of the new star which is discovered with peak electromagnetic wavelength of 400.00 nm is 7225 kelvin.

Learn more about the surface temperature here;

https://brainly.com/question/24478606