Question

The mass of a single palladium atom is 1.77×10-22 grams. How many palladium atoms would there be in 201 milligrams of palladium?

Answer 1

The mass of single palladium atom is $1.77\times 10^{-22}g$. Thus, in 1 gram of palladium, the number of atoms will be:

$N=\frac{1}{1.77\times 10^{-22}}=5.65\times 10^{21} atoms$

Now,

$1 g\rightarrow 5.65\times 10^{21} atoms$

Also,

$201 mg=201\times 10^{-3}g$

Thus,

$201\times 10^{-3}g\rightarrow 201\times 10^{-3}\times 5.65\times 10^{21} atoms=1.35\times 10^{21} atoms$

Therefore, number of atoms in 201 milligrams of palladium will be $1.35\times 10^{21} atoms$.

Answer 2

Answer: The number of palladium atoms is $113.6\times 10^{19}$

Explanation:

We are given:

Mass of single palladium atom = $1.77\times 10^{-22}g$

Total mass of palladium = 201 mg = $201\times 10^{-3}g$    (Conversion factor: 1 g = 1000 mg)

To calculate the number of palladium atoms, we divide the total mass of palladium to the mass of one palladium atom.

$n=\frac{\text{Total mass of palladium}}{\text{Mass of one palladium atom}}$

Putting values in above equation, we get:

$n=\frac{201\times 10^{-3}g}{1.77\times 10^{-22}g}\\\\n=113.6\times 10^{19}$

Hence, the number of palladium atoms is $113.6\times 10^{19}$