Respuesta :
Answer:
It is given that the volume of a cone = [tex]3 \pi x^{3}[/tex] cubic units
Volume of cone with radius 'r' and height 'h' = [tex]\frac{1}{3} \pi r^{2}h[/tex]
Equating the given volumes, we get
[tex]3 \pi x^{3}[/tex]=[tex]\frac{1}{3} \pi r^{2}h[/tex]
[tex]r^{2} h =3 \times 3 x^{3}[/tex]
[tex]r^{2} h =9 x^{3}[/tex]
It is given that the height is 'x' units.
Therefore, [tex]r^{2} x =9 x^{3}[/tex]
[tex]r^{2} =9 x^{2}[/tex]
Therefore, r = 3x
So, the expression '3x' represents the radius of the cone's base in units.
Answer: The volume given is 3Pi(x^3) and the radius is x. The formula for the volume of a cone is V= [1/3]Pi(r^2)*height => [1/3]Pi (r^2) x = 3Pi(x^3) => (r^2)x = 3*3(x^3) => (r^2)x = 9(x^3) => (r^2) = 9x^2 => r = sqrt[9x^2] = 3x.
So THE CORRECT Answer is: A) r = 3x
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