The generic equation of the line is given by:
[tex] y = mx + b [/tex]
Where,
m: slope of the line
b: cutting point with vertical axis
The slope of the line is:
[tex] m = 3 [/tex]
The cut point with the vertical axis is:
[tex] b = 2 [/tex]
Thus, substituting in the generic equation of the line we have:
[tex] y = 3x + 2 [/tex]
Answer:
The equation of the line is given by:
[tex] y = 3x + 2 [/tex]
