Which parabola has the graph shown?
I think the answer is C. however, I'm not 100% sure.


[tex]x=m(y-k)^2+h\\\\(h,\ k)-the\ vertex[/tex]
We have the vertex (-4, -1), therefore we have:
[tex]x=(y-(-1))^2-4\ \ \ |+4\\\\(x+4)=(y+1)^2[/tex]
The equation of the parabola is ( x+4 )= ( y + 1 )². Then option C is correct.
A parabola is a curve in such a way that its distance from the focus and the directrix is the same from every point on the curve.
The equation of the parabola is calculated as:-
x = m ( y-k )² + h
The vertex coordinates are -4 and -1. Put the coordinates (-4,-1) in the equation above.
x = m ( y-(-1 ) )² - 4
x+4 = ( y + 1 )²
The equation of the parabola will be x+4 = ( y + 1 )². Hence, option C is correct.
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