Answer:
An arrow at a speed as high as 102 m/s straight up will travel 530.82 m height
Explanation:
We know the equation of motion [tex]v^2=u^2+2as[/tex], where s is the displacement, u is the initial velocity, a is the acceleration and v is the final velocity.
In this case body is projected straight up, so final velocity = 0 m/s, initail velocity = 102 m/s, acceleration = -9.8 [tex]m/s^2[/tex] and we need to find displacement, that is the height traveled by arrow.
Substituting
[tex]0 = 102^2-2*9.8*s\\ \\ s = 530.82 m[/tex]
So height traveled by arrow = 530.82 m