Question

Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).

Answer 1

we are given

$\sqrt{30} *\sqrt{610}$

we can radical formula

$\sqrt{a} *\sqrt{b}=\sqrt{a*b}$

we get

$\sqrt{30} *\sqrt{610}=\sqrt{30*610}$

$\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}$

we can  also write as

$\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}$

$\sqrt{30} *\sqrt{610}=10\sqrt{183}$............Answer

Answer 2

The product of $\sqrt {30}$ and $\sqrt {610}$ is $\boxed{\sqrt {18300} }$ or $\boxed{10\sqrt {183} }.$

Further Explanation:

The product of two square root numbers can be expressed as follows,

$\boxed{\sqrtx  \times \sqrt y  = \sqrt {x \times y} }$

Given:

The expression is $A = \sqrt {30}  \times \sqrt {610}.$

Explanation:

A expression than contain the ${n^{th}}$ root is known as the radical equation.

The symbol of the radical is $\sqrt[n]{x}.$

The radic and is a number that is in the radical.

The given expression is $A = \sqrt {30}  \times \sqrt {610}.$

Solve the expression to obtain the product of the numbers.

$\begin{aligned}A&= \sqrt {30}\times \sqrt {610}\\&= \sqrt {30 \times 610}\\&= \sqrt {18300}\\&= \sqrt {183 \times 100}\\&= 10\sqrt {183}\\\end{aligned}$

The product of $\sqrt {30}$ and $\sqrt {610}$ is $\boxed{\sqrt {18300} }$ or $\boxed{10\sqrt {183} }.$

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function https://brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponents and Powers

Keywords: standard dorm, product, square root 30, square rot 610, express, radical expression, expression, factors, simplest form, square root, radicand, cube root, constant term.