Question

Find the indicated trigonometric value in the specified quadrant. Function quadrant trigonometric value csc θ = –5 iii cot θ

Answer 1

csc = 1/sin, so sin= -1/5

sin²+cos²=1 so sin=√(24/25)=2√6/5

cot=cos/sin or 2√6/5 * -5/1 = -2√6