fyt as per the question the magnitude of two like charges are given as q1 and q2.the separation distance is given as r unit.hence the potential energy is given as-[tex]P.E=+\frac{1}{4\pi\epsilon} \frac{q1*q2}{r^2}[/tex]
here the potential energy is positive which means the force between two charges is repulsive.the potential energy is maximum which indirectly denotes that the system is unstable.due to this repulsion the smaller charge may accelerate.
coming to the same charges of opposite nature i.e unlike charges-here the magnitude of charges are same and separation distance is also are,so the potential energy will be given as-[tex]P.E=-\frac{1}{4\pi\epsilon}\frac{q1*q2}{r^2}[/tex]
here the potential energy is negative .so the system of two charges are attracted by each other.
Answer:
1-the electric potential energy between like charges is positive.
2-the electric potential energy between unlike charges is negative.
Explanation:
1- the electric potential energy is positive between like charges because the energy is used to bring the charges closer as they repel each other or the work is being done in the direction of the electric field.
2- the electric potential is negative between unlike charges because one of them has a negative sign and opposite signs do not cancel each other furthermore the work is done against the electric field i.e is keeping the charges away from each other as unlike charges attract each other.
