Respuesta :
Area of equilateral triangle = s²√3/4
Where s = length of side
s = 6
Area, A = s²√3/4 = 6²√3/4 = 36*√3/4 = 9√3
A = 9√3 = 9 * 1.732 ≈ 15.588
A ≈ 15.6 in² to the nearest tenth. (B)
Where s = length of side
s = 6
Area, A = s²√3/4 = 6²√3/4 = 36*√3/4 = 9√3
A = 9√3 = 9 * 1.732 ≈ 15.588
A ≈ 15.6 in² to the nearest tenth. (B)
Answer:
(B)[tex]15.6 in^2[/tex]
Step-by-step explanation:
Given: A piece of art is in the shape of an equilateral triangle with sides of 6 in.
To find: The area of the piece of art.
Solution: Since, the piece of art is in the shape of an equilateral triangle, thus the area of equilateral triangle=[tex]\frac{\sqrt{3}}{4}{\times}(side)^{2}[/tex]
=[tex]\frac{\sqrt{3}}{4}{\times}(6)^2[/tex]
=[tex]\frac{\sqrt{3}}{4}{\times}6{\times}6[/tex]
=[tex]9\sqrt{3}[/tex]
=[tex]9(1.732)[/tex]
=[tex]15.6 in^2[/tex]
Therefore, area of the piece of art=[tex]15.6 in^2[/tex]