A piece of art is in the shape of an equilateral triangle with sides of 6 in. Find the area of the piece of art. Round your answer to the nearest tenth

A. 12.7 in2
B. 15.6 in2
C. 31.2 in2
D. None of these

Respuesta :

Area of equilateral triangle =   s²√3/4

Where s = length of side

s = 6

Area, A = s²√3/4 = 6²√3/4  = 36*√3/4 = 9√3

A = 9√3 = 9 * 1.732 ≈ 15.588

A ≈ 15.6 in²   to the nearest tenth. (B)

Answer:

(B)[tex]15.6 in^2[/tex]

Step-by-step explanation:

Given:  A piece of art is in the shape of an equilateral triangle with sides of 6 in.

To find: The area of the piece of art.

Solution: Since, the piece of art is in the shape of an equilateral triangle, thus the area of equilateral triangle=[tex]\frac{\sqrt{3}}{4}{\times}(side)^{2}[/tex]

=[tex]\frac{\sqrt{3}}{4}{\times}(6)^2[/tex]

=[tex]\frac{\sqrt{3}}{4}{\times}6{\times}6[/tex]

=[tex]9\sqrt{3}[/tex]

=[tex]9(1.732)[/tex]

=[tex]15.6 in^2[/tex]

Therefore, area of the piece of art=[tex]15.6 in^2[/tex]

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